The differenc beyween two numbers is 100. if 4 % of the larger number is 1more than 6% of smaller number. find the sum of the two numbers
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Let x be the larger no & y be the smaller no
x - y = 100 - - - - - (i)
x = 100 + y
4% of x = 6% of y + 1
0.04 x = 0.06 y + 1
4x-6y = 100
2x-3y = 50 - - - - - (ii)
2(100 + y) - 3y = 50
200 + 2y - 3y = 50
y = 150
x = 100 + y = 100 + 150 = 250
x + y = 250 + 150 = 400
x - y = 100 - - - - - (i)
x = 100 + y
4% of x = 6% of y + 1
0.04 x = 0.06 y + 1
4x-6y = 100
2x-3y = 50 - - - - - (ii)
2(100 + y) - 3y = 50
200 + 2y - 3y = 50
y = 150
x = 100 + y = 100 + 150 = 250
x + y = 250 + 150 = 400
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