The difference between 2 two digit numbers formed by the transposition of their digits is equal to one fifth of one of the numbers.Can you find the two numbers?
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Lets xy is a two digit number.
From the question, we have to check for xy−yx
xy−yx=(10x+y)−(10y+x)=9x−9y=9(x+y)
Which is always divisible by 9.
Hence the difference of a two digit number and the number obtained by reversing the digit is always divisible by 9.
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