Math, asked by raunakkatiyar2, 11 months ago

the difference between a 2 digit number and the number obtained by interchanging the digit is 18 .what is the original number ,if tge ratio between the digits of the number is 1:3​

Answers

Answered by lokeshsekkizhar
0

Answer:

original number = -13

Step-by-step explanation:

let x be in 10th place

and y be in 1st place

therefore original number = (x*10) + y

and interchanged number = (y*10) + x

given: (x*10 + y) - (y*10 + x) = 18

          as the numbers are in ratio 1:3

       => y = 3x

using y = 3x in the equation

=> (10x + 3x) - (30x + x) = 18

=> 13x - 31x = 18

=> -18x  = 18

=> x = 18/-18

=> x = -1

using x = -1 in y = 3x

=> y = 3(-1)

y = -3

therefore original number = x(10) + y

= -10 + (-3)

= -10 -3

original number = -13

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