Question

The difference between a 2-digit number
and the number formed by reversing its
digits is 72. Also, the sum of twice the tens
digit and 4 times the ones digit is 22. Find
the number.​

Answer 1

Answer:

91

Step-by-step explanation:

Let the tens digit be x

Let ones digit be y

The number = (10 x + y)

Reversed number = (10 y + x)

Acc. to condition,

10x + y - (10 y +x) = 72

10x + y - 10y - x = 72

9x - 9y = 72

9(x-y) = 72

x-y = 72/9

x-y = 8 ---(1)

According to second condition,

2x + 4y = 22 ---(2)

Lets Solve

(x - y = 8) x 4                        4x - 4y = 32

2x + 4y = 22                         2x + 4y = 22

                                            --------------------

                                             6x = 54

                                                x = 9

substituting,

x - y = 8

9 - y = 8

9-8 = y

y = 1

Therefore, The number is :

10 x + y

90 + 1

91

Answer 2

Step-by-step explanation:

let the ten digit be X

10x+y

y=1

X=9

so according to question

90+1

91 is the answer