The difference between a 2-digit number and the number obtained by interchanging its digit is 63.what is the difference between the digits of the
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Answered by
192
Hey.. I think this can be ur answer!!
Let the number be 10y + x
Reversed number = 10x+y
Difference - 10y+x-(10x+y) = 63
9y - 9x =63
y-x= 7
So difference between digits of the number is 7
Hope it helps you dear ☺️☺️
Have a great time!!
Let the number be 10y + x
Reversed number = 10x+y
Difference - 10y+x-(10x+y) = 63
9y - 9x =63
y-x= 7
So difference between digits of the number is 7
Hope it helps you dear ☺️☺️
Have a great time!!
Answered by
124
Let the number be 10x + y.
After interchanging it's digits, We get a number : " 10y + x "
Given,
10x + y - ( 10y + x ) = 63
9x - 9y = 63
9 ( x - y) = 63
( x - y) = 7 .
We know that, x, y are the digits. We found x - y = 7 .
So ,The difference between the digits of the number is 7
After interchanging it's digits, We get a number : " 10y + x "
Given,
10x + y - ( 10y + x ) = 63
9x - 9y = 63
9 ( x - y) = 63
( x - y) = 7 .
We know that, x, y are the digits. We found x - y = 7 .
So ,The difference between the digits of the number is 7
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