Question

the difference between a 2-digit number obtained by interchanging the position of its digit is 72 .find the difference between the two digits of that numbers.​

Answer 1

Let the digits be x and y.

Thus original number is = 10x + y

Now interchange the digits and we get

New number = 10y + x

According to question

10x + y - ( 10y + x ) = 72

10x + y - 10y - x = 72

9x - 9y = 72

9 ( x - y ) = 72

x - y = 8

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Answer 2

Let the numbers be x and y

'y' at once place and '10x' as the tens place

So the digits will be 10x+y

After interchanging = 10y+x

Difference between the digits and interchange is 72.

10x+y-(10y+x) = 72

9x-9y= 72

x-y = 8

The difference between these two numbers is 8.