the difference between a 2-digit number obtained by interchanging the position of its digit is 72 .find the difference between the two digits of that numbers.
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Let the digits be x and y.
Thus original number is = 10x + y
Now interchange the digits and we get
New number = 10y + x
According to question
10x + y - ( 10y + x ) = 72
10x + y - 10y - x = 72
9x - 9y = 72
9 ( x - y ) = 72
x - y = 8
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Answered by
1
Let the numbers be x and y
'y' at once place and '10x' as the tens place
So the digits will be 10x+y
After interchanging = 10y+x
Difference between the digits and interchange is 72.
10x+y-(10y+x) = 72
9x-9y= 72
x-y = 8
The difference between these two numbers is 8.
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