Question

The difference between a three digit number and a number formed by reversing its digits is 198. Determine the number, if the sum of the digits is 5.

Answer 1

Answer:

ASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASASASDASDAS

ASD ASAS

Step-by-step explanation:

Answer 2

Answer:

311

Step-by-step explanation:

We are given that a three digit number

Let unit place of a number=z

Tens place of a number =y

Hundred place of a number =x

Then number will be=100 x+10 y+z

After reversing its digits then obtained number =100 z+10 y+x

According to question

$100 x+10 y+z-100 z-x-10 y=198$

$99 x-99 z=198$

$99(x-z)=198$

$x-z=2$

$x=z+2$

$x+y+z=5$

Substitute the value of x in equation then we get

$z+2+y+z=5$

$2z+y=5-2$

$2z+ y=3$

When z=1 and y=1 then

$2(1)+1=3$

$x=z+2=1+2=3$

Hence, the number =100(3)+10(1)+1=311