Question

the difference between a three digit number and number formed by reversing its digits id 198. find the difference of its first and past digit

Answer 1

Let the digit be 100x + 10y + z
Let the reversed number be 100z + 10y + z
Their difference = 198
100x + 10y + z - (100z + 10y +x) = 198
100x - x + 10y - 10y + z - 100z = 198
99x - 99z = 198
99 (x - z) = 198
x - z = 198 / 99
= 2
Therefore, x - z = 2

Answer 2

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