Math, asked by Joyson9538, 1 year ago

The difference between a three digit number and the number formed by reversing its first two digits is 450. If the sum of the number is 10. Determine the number

Answers

Answered by waqarsd
7
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Answered by hukam0685
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The three digit numbers may be 613 or 721.

Given:

  • The difference between a three digit number and the number formed by reversing its first two digits is 450.
  • If the sum of the number is 10.

To find:

  • Determine the number.

Solution:

Concept to be used:

  • Assume all three digits of number.
  • Form equation by extended form of number.
  • Solve both equations and find the number.

Step 1:

Let the digits of number are x,y, and z from left to write.

So,

The number may be written as

100x + 10y + z

The number obtained by reversing first two digits are

100y + 10x + z \\

ATQ,

100x + 10y + z - 100y - 10x - z = 450 \\

or

90x - 90y = 450 \\

or

\bf x - y = 5...eq1 \\

Step 2:

Form another equation by adding it's digits.

\bf x + y + z = 10...eq2 \\

Now analyse the eq1 and eq2 to find the numbers.

Case 1:

Difference between first two terms are 5,

Thus, first two terms may be 6 and 1

so, last digit will be 3.

Thus,

Number will be 613.

Verification:

613-163= 450

Case 2:

Thus, first two terms may be 7 and 2

so, last digit will be 1.

Thus,

Number will be 721.

Verification:

721-271=450

Case 3:

Thus, first two terms may be 5 and 0

so, last digit will be 5.

Thus,

Number will be 505.

Verification:

505-050≠450

Thus,

The three digit numbers may be 613 or 721.

Learn more:

1) the sum of a two digit number and the number obtained by reversing the digit is 66 if the digit of the number differ by ...

https://brainly.in/question/3096111

2) a two digit number whose unit digit is(a+b)and tens digit (a-b) is______. (a) 9a-11b (b) 9a+11b (c) 11a+9b (d) 11a-9b

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