The difference between a three digit number and the number formed by reversing digits is divisible by
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it can be anything it depends on number
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2
Answer:
99
Step-by-step explanation:
Let the number be = 100a+10b+c
So the reverse is = 100c+10b+a
Subtracting the two equation = 99a-99c
= 99(a-c)
∵ divisible by 99
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