Question

the difference between a two-digit number and the number obtained by interchanging the digits is9. find the difference between the two digits of that number.​

Answer 1

[tex]\texbf{Let the unit's digit be y and ten's digit be x. }[/tex]

[tex]\texbf{Then, the number =10x+y. When we interchange the digits, the number will be 10y+x. }[/tex]

Now, it is given that the difference between a two digit number and the number obtained by interchanged the two digits of the number is 9, therefore, we have:

[tex]\texbf{(10x+y)−(10y+x)=9 }[/tex]

[tex]\texbf{⇒9x−9y=9 }[/tex]

[tex]\texbf{⇒9(x−y)=9 }[/tex]

$\texbf{⇒x−y=  9/9}$

[tex]\texbf{ ⇒x−y=1 }[/tex]

$\texbf{Hence, the difference between the two digits of number is 1.}$

MARK AS BRAINLAIST

Answer 2

Answer:

1

Step-by-step explanation:

let the 2 digit no = 10x+y ---A

when interchanged 2 digit no = 10y+x ---B

difference can be A-B or B-A

A-B =

10x-x +y-10y = 9(x-y) = 9

x-y = 9/9 =1

B-A =

10y-y+x-10x = 9(y-x) =9

y-x =9/9 =1

difference between 2 digits =1