Question

The difference between a two-digit number and the number obtained by reversing the digits is 63. If the sum of the digits in the number is 11. then what is the sum of the numbers?​

Answer 1

Step-by-step explanation:

Let the numbers be x and y

the number at ones place is y

and number on tens place is 10x

so the digit will be 10x+y

The interchange of digit is =10y+x

It is given the difference between the digit and interchange is 63 so

10x+y−(10y+x)=63

9x−9y=63

x−y=7

The difference between the digits is 7.

solution

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