The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. How many such pairs are possible?
a) 4 b) 5 c) 6 d) 7
Answers
Answered by
0
Answer:
Let the ten's digit be x and unit's digit be y.
Then, (10x+y)−(10y+x)=36
9(x−y)=36
x−y=4
Therefore, the difference between the two digit of that number is 4
(A) 4
Similar questions