Math, asked by keesaravenkatesh99, 19 days ago

The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. How many such pairs are possible?

a) 4 b) 5 c) 6 d) 7​

Answers

Answered by anilvedu17
0

Answer:

Let the ten's digit be x and unit's digit be y.

Then, (10x+y)−(10y+x)=36

9(x−y)=36

x−y=4

Therefore, the difference between the two digit of that number is 4

(A) 4

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