Question

The difference between a two-digit number and the number obtained by interchanging the digits is 36. What is the difference between the sum and the difference of the digits of the number if their ratio between the digits of the number is 1:2 ?

Answer 1

Here's your answer I got the original no. for you ...... if should I solve the ratio part plz.. specify the question again with appropriate English...

Answer 2

Answer:

The sum is 12 and difference is 4

Step-by-step explanation:

Given the two digit number be xy=10x+y

The new number obtained by interchanging the digit=yx=10y+x

Now, given the difference between the above two is 36

⇒ (10x+y)-(10y+x)=36

⇒ 10x-x-10y+y=36

⇒ 9x-9y=36

⇒ x-y=4

Also, given ratio is 1:2

⇒ $\frac{y}{x}=\frac{1}{2}$

⇒ x=2y

Put thus value in above, we get

x-y=4 ⇒ 2y-y=4 ⇒ y=4

Hence, x=2(4)=8

Hence, the sum is x+y=8+4=12

The difference is x-y=8-4=4