Question

The difference between age of two brothers is 3 years. 5 years ago, the younger was 2/5 times the age of elder brother. Find their present age.

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Answer 1

Explanation:

let the age of elder brother 5yrs ago be x

age of younger brother 2x/5

a/q x-2x/5=3

=3x/5=3

x=5×3/3

x=5

present

age of elder brother 5+5=10

younger brother=2×5/5+5=2+5=7

Answer 2

Given :-

• The difference between age of two brothers is 3 years.

• 5 years ago, the younger was 2/5 times the age of elder brother.

To Find :-

• What are their present ages?

Solution :-

Let the present age of elder brother be x years and the age of younger brother will be y years.

As per question :-

Given that,

The difference between age of two brothers is 3 years.

Therefore,

x - y = 3

⟼ x = 3 +y............ eq(1)

Again, it’s given that

5 years ago, the younger was 2/5 times the age of elder brother.

5 years ago,

Age of elder brother = ( x -5) years

Age of younger brother = (y -5) years

According to the question :-

2/5 ( x -5) = ( y -5)

⟼ 2x -10 = 5y -25

⟼ 2x -5y = -25 +10

⟼ 2x -5y = -15.............eq(2)

Put x = 3 + y in eq(2)

⟼ 2x -5y = -15

⟼ 2 ( 3 + y) - 5y = -15

⟼ 6 + 2y -5y = -15

⟼ y = 7

To get the value of x, put y = 7 in eq(1)

x = 3 + y

⟼ x = 3 + 7

$⟼x = 10$

Hence,

the present age of elder brother is = 10 years

The present age of younger brother is = 7 years