Math, asked by farukhumar983, 1 year ago

the difference between age of two brothers is 3 years five years ago the younger was 2/5 times the age of elder brother and their present age

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Answered by SillySam
5
Heya mate, Here is ur answer

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Let the ages of two brothers be x and y.

x-y=3

x=3+y--------(1)

Five years ago,

x's age = x-5

y's age = y-5

A/Q,

y-5= 2/5(x-5)

y-5=2x-10/5

5(y-5)=2x-10

5y-25=2x-10

5y-2x=-10+25

5y-2x=15

From equation 1 , we have x=3+y,

so 5y-2(3+y)=15

5y-6-2y=15

3y=15+6

3y=21

y=21/3

y=7 .

x=3+y

x=3+7

x=10


<b><u>So, the ages of two brothers are 7 and 10 years. </u></b>


<b>❤Hope the answer helps you❤</b>

Warm regards

@Laughterqueen

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