the difference between age of two brothers is 3 years five years ago the younger was 2/5 times the age of elder brother and their present age
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Heya mate, Here is ur answer
![\huge\boxed{ \red{ \mathfrak{answer}}} \huge\boxed{ \red{ \mathfrak{answer}}}](https://tex.z-dn.net/?f=+%5Chuge%5Cboxed%7B+%5Cred%7B+%5Cmathfrak%7Banswer%7D%7D%7D)
Let the ages of two brothers be x and y.
x-y=3
x=3+y--------(1)
Five years ago,
x's age = x-5
y's age = y-5
A/Q,
y-5= 2/5(x-5)
y-5=2x-10/5
5(y-5)=2x-10
5y-25=2x-10
5y-2x=-10+25
5y-2x=15
From equation 1 , we have x=3+y,
so 5y-2(3+y)=15
5y-6-2y=15
3y=15+6
3y=21
y=21/3
y=7 .
x=3+y
x=3+7
x=10
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![<b>❤Hope the answer helps you❤</b> <b>❤Hope the answer helps you❤</b>](https://tex.z-dn.net/?f=%26lt%3Bb%26gt%3B%E2%9D%A4Hope+the+answer+helps+you%E2%9D%A4%26lt%3B%2Fb%26gt%3B)
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Let the ages of two brothers be x and y.
x-y=3
x=3+y--------(1)
Five years ago,
x's age = x-5
y's age = y-5
A/Q,
y-5= 2/5(x-5)
y-5=2x-10/5
5(y-5)=2x-10
5y-25=2x-10
5y-2x=-10+25
5y-2x=15
From equation 1 , we have x=3+y,
so 5y-2(3+y)=15
5y-6-2y=15
3y=15+6
3y=21
y=21/3
y=7 .
x=3+y
x=3+7
x=10
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
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