Math, asked by brainlymember432, 3 months ago

the difference between ages of ravi and geeta is 10 years. if 5 years earlier ravi was twice as old as geeta, find there present age​

Answers

Answered by Aloneboi26
59

Step-by-step explanation:

Answer:

Their present ages are:

Ravi's age = 25 years

Geeta's age = 15 years

Step-by-step explanation:

Given that:

The difference between ages of Ravi and Geeta is 10 years.

5 years earlier Ravi was twice as old as Geeta.

To Find:

Their present ages.

Ravi is greater than Geeta as 5 years earlier Ravi was twice as old as Geeta.

Let us suppose:

The age of Ravi be S years.

Then Geeta's age will be (S - 10) years.

5 years earlier their ages:

Ravi's age = (S - 5) years

Geeta's age = 2(S - 10 - 5) years

Finding their present ages:

According to the question,

⇒ (S - 5) = 2(S - 10 - 5)

⇒ S - 5 = 2S - 20 - 10

⇒ 2S - S = 20 + 10 - 5

⇒ S = 25

Their ages present are:

Ravi's age = S = 25 years

Geeta's age = (S - 10) = (25 - 10) = 15 years

Answered by IlAloneboiIl
2

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Their present ages are:

Ravi's age = 25 years

Geeta's age = 15 years

Step-by-step explanation:

Given that:

The difference between ages of Ravi and Geeta is 10 years.

5 years earlier Ravi was twice as old as Geeta.

To Find:

Their present ages.

Ravi is greater than Geeta as 5 years earlier Ravi was twice as old as Geeta.

Let us suppose:

The age of Ravi be S years.

Then Geeta's age will be (S - 10) years.

5 years earlier their ages:

Ravi's age = (S - 5) years

Geeta's age = 2(S - 10 - 5) years

Finding their present ages:

According to the question,

⇒ (S - 5) = 2(S - 10 - 5)

⇒ S - 5 = 2S - 20 - 10

⇒ 2S - S = 20 + 10 - 5

⇒ S = 25

Their ages present are:

Ravi's age = S = 25 years

Geeta's age = (S - 10) = (25 - 10) = 15 years

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