Math, asked by GoolNight0010, 3 days ago

The difference between ages of ravi and geeta is 10 years. if 5 years earlier ravi was twice as old as geeta, find there presen agee​

Answers

Answered by Anonymous
11

\huge{\underline{\mathtt{\red{Ꭺ}\red{ղ}\green{Տ}\blue{ω}\purple{Ꭼ}\orange{я᭄}}}}

Let Arjun be designated as A

Let Shriya be designated as S.

A is twice as old as S

Let S be x years old currently.

Therefore A is 2(x) years old currently.

5 years ago S was ( x - 5 ) years old

5 years ago A was (2(x) - 5) years old

5 years ago A was three times S' age.

That is, 5 years ago, ( 2x - 5 ) = 3( x - 5 )

or

2x - 5 = 3x - 15 so

3x - 2x = -5 + 15 or

x = 10

I stated that S' Current age was x years old. We have now identified x as 10 years old.

A is therefore identified as 2x years old or 20 years old.

Therefore currently Arjun and Shryia are 20 and 10 years old respectively.

PB

PP Note that 5 years ago A was 15 and S was 5, so A was three times S' age.

Answered by 1910h
1

Step-by-step explanation:

Present age of Seema is 20 then according to question age of Geeta is 40.

If we suppose that x years ago Geeta was three times Seema's age then

x years ago Seema's age=20−x

then age of Geeta is =40−x

Now,

3(20−x)=40−x ( ∵x years ago age of Geeta was three times of Seema and if we want to equal the two ages then we have to multiple by 3 with the age of Seema. )

⇒60−3x=40−x

⇒−3x+x=40−60

⇒−2x=−20

⇒x=

2

20

=10years

Similar questions
Math, 3 days ago