the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n+1)' sides is equal to 5° ; find the value of 'n'
STEP BY STEP
IF U DON'T KNOW THEN DON'T ANSWER PLS
Answers
Answered by
6
Answer:
sum of exterior angle of polygon is 360
360/n-360 (n+1)=12
360 (n+1)-360n=12n (n+1)
12n^2+12n=360
n^2+n-30=0
(n-5)(n+6)=0
n=5,n=-6
n=5
Answered by
14
Answer:
Extr angle= 360/n
360/n-360/n+1 = 5
multiply by n(n+1)
(n+1) 360-360n=5n(n+1)
360n+360-360n=5n2+5n
5 n2+5n-360= 0
n2+n-72=0
n2+9n-8n-72=0
n(n+9)-8(n +9)=0
(n+9), (n-8)
n-8=0
n=8. Ans
Similar questions