The difference between any two consecutive interior angles of a polygon is 5°. If smallest angle is 120°, find the number of sides of the polygon.
Do not copy.
Answers
Answered by
11
Smallest angle=120degree
Common difference=5
A P is 120, 125, 130,……..
The sum of interior angles of a polygon= (n-2)180
Hence Sum of n terms of an A P = (n-2)180
n/2 {2.120+(n-1)5} = 180(n-2)
5n^2 -125n +720 = 0
n^2 -25n +144=0
n=9 or 16
hence number of sides can be 9 or 16
Common difference=5
A P is 120, 125, 130,……..
The sum of interior angles of a polygon= (n-2)180
Hence Sum of n terms of an A P = (n-2)180
n/2 {2.120+(n-1)5} = 180(n-2)
5n^2 -125n +720 = 0
n^2 -25n +144=0
n=9 or 16
hence number of sides can be 9 or 16
Answered by
3
Answer:
Step-by-step explanation:
Attachments:
Similar questions