The difference between C. I and S. I for 2 years at 10% per annum is rs. 50. Find the sum
Answers
Answer:
Let P be the sum.
SI = P * 2 * 10/100
SI = 0.2 P
CI = P * (1 + 10/100)^2 - P
CI = P * 1.1^2 - P
CI = 1.21 P - P
CI = 0.21 P
Given,
CI - SI = 50
0.21 P - 0.2 P = 50
0.01 P = 50
P = 50/0.01
P = 5000
So, the sum is Rs. 5,000/-.
Step-by-step explanation:
Let P be the sum.
SI = P * 2 * 10/100
SI = 0.2 P
CI = P * (1 + 10/100)^2 - P
CI = P * 1.1^2 - P
CI = 1.21 P - P
CI = 0.21 P
Given,
CI - SI = 50
0.21 P - 0.2 P = 50
0.01 P = 50
P = 50/0.01
P = 5000
So, the sum is Rs. 5,000/-.
OR
A = P(1+r/100)^n
CI = A - P = P(1+r/100)^n - P.
SI = Pnr/100
[ Here, P = sum, r = rate of interest =10% , n = no. of years = 2, A = Sum + Interest, CI = Compound Interest and SI = Simple Interest ]
As per questions, CI - SI = 50
Or, [P(1+r/100)^n - P] - Pnr/100
Or, P[(1+10/100)^2 - 1 - 2*10/100] = 50
Or, P * 1/100 = 50
Or, P = 5000