Question

the difference between compound and s.i on a sum of money deposited for 2 year at 5percentage per annum os rupees 12 find the sum of money plz answer me fast ​

Answer 1

Step-by-step explanation:

$\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

Answer:

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Step-by-step explanation:

N=2years

R=5 %

We have S.I.=

100

PNR

=

100

P×2×5

=

100

10P

=0.1P

And on interest being compounded for 2 years and R=5 %, Amount=P(1+

100

R

)

N

=P(1+

100

5

)

2

=P×(1.05

2

)=1.1025P

So, C.I.=A−P=1.1025P−P=0.1025P

Given, C.I.−S.I=Rs12

=>0.1025P−0.1P=Rs12

=>0.0025P=Rs12

=>P=Rs4,800