Question

the difference between compound and simple interest on certain sum of money for 3 years at 6 2/3 % p.a is rs 18 4 find the sum​

Answer 1

Answer:

The required sum is Rs 3375

Step-by-step explanation:

Suppose sum=P

Given CI−SI=Rs.122

P(1+

100

5

​

)

3

−P−(

100

P×5×3

​

)=122

P(

100

3

105

3

​

−1−

100

15

​

)=122

P(

100

3

7,625

​

)=122

P=

7,625

122×100

3

Compound interest for 2 years=Rs.832

Simple interest for 3 years=Rs.1200

As simple interest for each year remains the same.

So, simple interest for 2 years=1200×

3

2

​

=Rs.800

We know that,

CI

2 year

​

−SI

2 year

​

=

200

SI

2 year

​

×R

​

=

(100)

2

PR

2

​

832−800=

200

800×R

​

32=4×R

R=8%

Again, CI

2 year

​

−SI

2 year

​

=

(100)

2

PR

2

​

32=

100

2

P×(8)

2

​

32=

10000

P×64

​

P=

64

32

​

×10000=5000

Hence, the principal is Rs.5000.

​

=Rs.16,000





Answer 2

Answer:

$\huge\mathfrak\red{hii \: mate}$

Step-by-step explanation:

Hope helpful for you