The difference between compound and simple interest on a certain principal at 15%per annum for 3 year is 2296.35rs. find the principal. ANSWER = 32400
Answers
Answer:
let p be the principal
ci=p(1+.15)^3=p1.52 si=p×.15×3=p0.45. ci-si=1.52p-.45p=1.07p=2296.35 So p=2296.35÷1.07=2146.12rs
Step-by-step explanation:
R = 15 %. (N=TIME)
T =3 years
p.a = 15÷3 = 5
suppose principal =100
SI = PTR÷100 = 100×3×15÷100 =45
COMPOUND INTEREST= P(1+R÷100)N
=100(1+15/100)3
LCM= 100×23/20×23/20×23/20
= 12167/80 = 152.09
CI =(15209/100-100) = 15209-10000/100 =
5209/100
Difference between CI-SI = 52.09-45 = 7.09
When the difference is = 7.09 - the principal is 100
when difference is 2296.35 = 100×100/709×229635/100 = 229635/709 =
rupees 32388.58
Thank you