Math, asked by mayurisalankar8679, 9 months ago

The difference between
compound
interest and simple interest on a certain
sum of money after 2 years at 10% rate of
interest is Rs. 200. Find the difference in
the interests after 3 years.​

Answers

Answered by hykokcha
1

Answer:

24.81

Step-by-step explanation:

For first year, S.I. = C.I.

Now, Rs. 16 is the S.I. on S.I. for 1 year.

∴ Rs. 10 is S.I. on Rs. 100

∴ Rs. 16 is S.I. on (  10

100  ×16)=Rs.160

∴ S.I. on principal for 1 year at 10% is Rs. 160.

∴ principal =(  

10×1

100×160

​  

)=Rs.1600.

Amount for 2 years compounded half yearly

=Rs.[1600×(1+  

100

5  ) 4

]=Rs.1944.81

∴C.I.Rs.(1944.81−1600)=Rs.344.81

S.I.=Rs.(  

100

1600×10×2  )=Rs.320

∴(C.I.)−(S.I.)=Rs.(344.81−320)=Rs.24.81

Hope it helps you .....

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