Math, asked by shubhamgupta53sg, 8 months ago

The difference between compound interest and simple interest on ₹x at 6.5% per annum for 2 years is ₹33.80. What is the value of x?

Answers

Answered by bhupesh4464
0

Answer:

Compound interest = x *(1 + 15/100)^2 - x

= x* (1.15^2 - 1) = x*(1.3225 -1) = 0.3225x

Simple interest = x* 15 * 2 / 100 = 30x / 100= 0.30 x

Difference between compound interest and simple interest = 0.3225x - 0.30 x = 0.0225 x

So, 0.0225 x = ₹9

Therefore, x = ₹400 Answer

Check:

Compound interest = 400 * (1.15)^2 - 400 = ₹129

Simple Interest = 400* 15 * 2/100 = ₹120

Difference = ₹129 - ₹120 = ₹9 ✓

Step-by-step explanation:

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Answered by Godfather7777
0

Answer: ₹8000

Step-by-step explanation:

Formula Used : Difference (for 2 year) = P (r/100)²


Calculation : According to the question,
33.8 = P (6.5/100)²
33.8 = P (65/1000)²
33.8 = P (65 × 65/1000× 1000)²
338 = P ( 65 × 65/100 × 1000)²
26 = P ( 5 × 65/100 × 1000)²
2 = P ( 5 ×5/100 × 1000)
2 = P ( 1/4000 )
P = 2 × 4000
P = 8000

Therefore Principle is ₹8000.

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