Question

the difference between compound interest and simple interest for 3 years at 10% per annum in 62 rupees find the sum​

Answer 1

${\tt{\red{\underline{\underline{\huge{Answer= \: 1.92}}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\LARGE{\bf{\underline{\underline\color{purple}{Given:-}}}}$

• $\sf\green{ Principal \: = \: ₹69 }$
• $\sf\green{ Rate \: = \: 10 }$
• $\sf\green{ Time \: = \: 3years }$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \blue{ SI \: for \: 3 \: years }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: \frac{ \: P \: \times \: R \: \times \: T \: }{100} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: \frac{ \: 62 \: \times \: 10 \: \times \: 3 }{100} \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: \frac{1860}{100} \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \displaystyle \sf \: ₹18.6 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Interest \: = \: ₹18.6 }} }\\ \\\end{gathered}\end{gathered}$

━━━━━━━━━━━━━━━━━━━━━━━━━

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \red{ For \: compound \: interest }}$

$\boxed{ \sf \blue{ Interest \: for \: 1st \: year }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: \frac{ \: 62 \: \times \: 10 \: \times \: 1 \: }{100} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Interest \: = \: ₹6.2 }} }\\ \\\end{gathered}\end{gathered}$

$\boxed{ \sf \red{ Principal \: for \: 2nd \: years }}$

₹ 62 + ₹ 6.2

$\fbox{₹68.2}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \blue{ Interest \: for \: 2nd \: year }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: \frac{ \: 68.2 \: \times \: 10 \: \times \: 1 \: }{100} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Interest \: = \: ₹6.82 }} }\\ \\\end{gathered}\end{gathered}$

$\boxed{ \sf \red{ Principal \: for \: 3rd \: year }}$

₹ 68.2 + ₹ 6.2

$\fbox{₹75.02}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \blue{ Interest \: for \: 3rd \: year }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: \frac{ \: 75.02 \: \times \: 10 \: \times \: 1 \: }{100} }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: Interest \: = \: ₹7.50 }} }\\ \\\end{gathered}\end{gathered}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \red{ Compound \: interest \:for \: 3 \: years }}$

• $\boxed{ \sf \pink{ Interest \: for \: the \: (1st\: +2nd \: +3rd\:) years }}$
• ₹6.2 + ₹ 6.82 + ₹ 7.50
• $\boxed{ \sf \purple{ ₹20.52}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\boxed{ \sf \blue{ Difference \: between \:CI \: and \: SI }}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: ₹20.52\: - \: ₹18.6 }} }\\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\: ₹1.92 }} }\\ \\\end{gathered}\end{gathered}$

$\boxed{ \sf \green{ So,\: difference \: between\: CI \: and \: SI \: = \: ₹1.92 }}$

━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

HI MATE.....

Good evening.....

Hope it helps u.....

♠ CHECK IT IS TOTAL THREE PAGES FOR SOLUTION...

HAVE A WONDERFUL DAY.....

MAKE ME AS BRAINLIEST......