The difference between compound interest and simple interest on a certain sum of money at 10% per annum for 2 years is rs.40/-. the sum is
Answers
Answered by
1
Simple Interest = PRT / 100
Let Principal be P
So,
SI = (P x 10 x 2) /100
SI = P/5
Compound Interest = P [( 1 + r/100 )^t - 1 ]
CI = P [ (1 + 10/100)^2 - 1 ]
CI = P [ ( 1.1 ) ^2 -1 ]
CI = P ( 1.21 - 1)
CI = 0.21 P
We are given, CI - SI = 40
So,
0.21 P - P/5 = 40
1.05 P - P = 200
0.05 P = 200
P = 200/0.05
Principal or Sum = 4000
Let Principal be P
So,
SI = (P x 10 x 2) /100
SI = P/5
Compound Interest = P [( 1 + r/100 )^t - 1 ]
CI = P [ (1 + 10/100)^2 - 1 ]
CI = P [ ( 1.1 ) ^2 -1 ]
CI = P ( 1.21 - 1)
CI = 0.21 P
We are given, CI - SI = 40
So,
0.21 P - P/5 = 40
1.05 P - P = 200
0.05 P = 200
P = 200/0.05
Principal or Sum = 4000
Answered by
0
Hello Dear.
Here is the answer---
Let the Sum of Money be Rs. P.
Given ⇒
Rate of Interest(R%) = 10%
Time(T) = 2 years.
Now,
∵ Simple Interest (S.I.) = (P × R × T)/100
= (P × 10 × 2)/100
= P/5
Now, Compound Interest = A - P.
= P(1 + r%/100)ⁿ - P
= P(1 + 10/100)² - P
= P(11/10)² - P
= P(121/100 - 1)
= P(21/100)
= 21P/100
According to the Question,
C.I. - S.I. = 40
⇒ 21P/100 - P/5 = 40
⇒ 21P - 20P = 40 × 100
⇒ P = 4000
⇒ P = Rs. 4000
∴ Sum of the Principal(P) is Rs. 4000.
Hope it helps.
Here is the answer---
Let the Sum of Money be Rs. P.
Given ⇒
Rate of Interest(R%) = 10%
Time(T) = 2 years.
Now,
∵ Simple Interest (S.I.) = (P × R × T)/100
= (P × 10 × 2)/100
= P/5
Now, Compound Interest = A - P.
= P(1 + r%/100)ⁿ - P
= P(1 + 10/100)² - P
= P(11/10)² - P
= P(121/100 - 1)
= P(21/100)
= 21P/100
According to the Question,
C.I. - S.I. = 40
⇒ 21P/100 - P/5 = 40
⇒ 21P - 20P = 40 × 100
⇒ P = 4000
⇒ P = Rs. 4000
∴ Sum of the Principal(P) is Rs. 4000.
Hope it helps.
Similar questions