the difference between exterior angle of a reglar polygon of n sides and regular polygon of n+1 sides is 5 degree what are the number of sides of the polygon
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Hey there,
i) Since interior and exterior angles of a polygon are liner pair, if the difference in interior angles is 5 deg then difference in exterior angles is also 5 deg.
ii) An exterior angle of a n sided polygon = 360/n and that of (n + 1) sided polygon is 360/(n + 1)
iii) ==> 360/n - 360/(n + 1) = 5
Taking LCM, simplifying and rearranging, n² + n - 72 = 0
Factorizing, (n + 9)(n - 8) = 0
==> Either n = -9 or 8
But n being a counting number, it cannot be negative.
So n = 8
Hope this helps!
i) Since interior and exterior angles of a polygon are liner pair, if the difference in interior angles is 5 deg then difference in exterior angles is also 5 deg.
ii) An exterior angle of a n sided polygon = 360/n and that of (n + 1) sided polygon is 360/(n + 1)
iii) ==> 360/n - 360/(n + 1) = 5
Taking LCM, simplifying and rearranging, n² + n - 72 = 0
Factorizing, (n + 9)(n - 8) = 0
==> Either n = -9 or 8
But n being a counting number, it cannot be negative.
So n = 8
Hope this helps!
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