Question

the difference between greatest and smallest perfect square roots whose whose square is 3 digit number​

Answer 1

Answer:

10

Step-by-step explanation:

In this question

We assume that smallest perfect square root is 1, because no number is smaller than 1.

and assume that perfect greatest square root is 121.

Therefore, $\sqrt{121}\ -\ \sqrt{1}$ = 11 -1 = 10

Square of 10 is 3 digit number.

$\mathbf{(10)^{2}\ =\ 100}$

Hence, 121 and 1 are the perfect square root and their difference is 10 whose square is 3 digit number.