Question

The difference between heat of reaction at constant pressure and at costant volume for the reaction. 2 C6H6 (l) + 15 O2 (g) ➡️12CO2(g) + 6H2O (l) at 25|degree Celsius in kj is ​

Answer 1

Answer:

∆H-∆E =nRT where ∆H is heat at constant pressure and ∆E is heat at constant volume there difference is equal to nRT where n is mole difference between product and reactant only in gaseous state (12-15) = -3 and R = 8.314 ×10^3 kj and Temperature = 298 Kelvin putting the value ∆H-∆E= (-3×8.314×1000×298) after solving -7432.7 ×10^3