The difference between heat of reaction at constant pressure and constant volume for the reac
given below at 25°C in kJ is:
Alg) +3BG) ► 0(g)
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The heat of reaction is basically ΔH at constant pressure and is ΔU at constant volume.
Since, for any reaction the relation between this heats is given by equation,
ΔH = ΔU + (Δn
g
)RT
where, Δn
g
= change in number of gaseous moles in any reaction.
Since, in the above reaction the only gaseous species are CO
2
and O
2
, so,
Δn
g
=12−15=−3.
Hence, using ΔH - ΔU = (Δn
g
)RT
ΔH - ΔU =(−3)RT=(−3)×8.314×298.15J (T in Kelvin)
=> ΔH - ΔU=7430J=7.43KJ
Hence, answer is option C.
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