Question

The difference between inside and outside surfaces of a cylindrical tube
14 cm long, is 88 cm². If the volume of the tube is 176 cm", find the inner
and outer radii of the tube.​

Answer 1

Step-by-step explanation:

hope you understand beta...........

Answer 2

Answer:

ANSWER

Consider R cm as the outer radius and r cm as the inner radius of the cylindrical tube

It is given that

Outside surface area - Inner surface ares =88

So we get

2 πrh−2 πrh=88

It can be written

2 π(R−r)h=88

By substituting the values

2×

7

22

×(R−r)×14=88

On further calculation

2×22×(R−r)×2=88

We get

R−r=88/(2×22×2)=1....(1)

We know that

Volume of the tube =176 cm

3

It can be written as

External volume -Inner volume =176

So we get

πR

2

h−πr

2

h=176

By taking common out

π(R

2

−r

2

)h=176

By substituting the values

7

22

×(R−r)(R+r)×14=176

Substituting equation (1)

22×1×(R+r)×2=176

We get

R+r=

(22×2)

176

=4....(2)

By adding both the equations

2R=5

So we get R=2.5 cm

By substituting r

2.5−r=1

So we get r=1.5 cm

Therefore, the inner and outer radii of the tube are 1.5 cm and 2.5 cm.