Math, asked by coolpurvi343, 11 months ago

The difference between outside and inside surfaces of a cylindrical metallic pipe 14 cm long is 44 CM square if the pipe is made of 88 cm cube of metal find inner and Outer radii of the pipe

Answers

Answered by abhi178
9
Let inner radius of pipe is r and outer radius of pipe is R .

then volume of pipe = π(R² - r²)L
88 = 22/7 × (R² - r²) × 14
88 = 44(R² - r²)
R² - r² = 2 ........(1)

area of pipe = 2π(R - r)L
44 = 2 × 22/7 × (R - r) × 14
R - r = 0.5 ......(2)

from equation (1) and (2),

R + r = 4 .....(3)

R = 2.25 cm and r = 1.75 cm
Answered by RiskyJaaat
3
HEY MATE !

HERE'S YOUR ANSWER ✌️✌️✌️✌️

r= inner radius 

R= outer radius 

h= height of the metallic pipe = 14 cm

Difference between the Curved surface area of the outer cylinder and Curved surface area of the inner cylinder  = 2πRh - 2πrh.

Given: 

difference between the outside and inside curved surface area of cylinder= 44 cm2 .

So, 

2πh( R - r) = 44

2 x 22/ 7 x 14 ( R - r) = 44

R - r = 1 / 2 

= 0.5

Given:

the pipe is made up of metal= 88 cm³

Volume of cylindrical metallic pipe = πR²h - πr²h.

So, 

22/7 x 14 (R² - r²) = 88

44 (R² - r²) = 88

(R² - r²) = 88 / 44

(R² - r²) = 2
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