the difference between prime number is represented as dp1,dp2.....dpn where dp n is difference between is difference between second and first prime number find sum of series where n = 24 given that 24th prime number is 89.
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25 prime no.s b/n 1 & 100 are
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
difference b/n two primes
dp1 =p2-p1= 3-2 =1
dp2 =p3-p2= 5-3 =2
...
dp24 = p25-p24 = 97-89 = 8
1, 2, 2, 4, 2, 4, 2, 4, 6, 2, 6, 4, 2, 4, 6, 6, 2, 6, 4, 2, 6, 4, 6, 8
sum = dP1 + .... + dP24 = 95
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