Question

the difference between S.I and C.I of 4000 for 2.5years @10%p.a is​

Answer 1

Answer:

82

Step-by-step explanation:

For S.I.

I= (4000×2.5×10)/100

= 1000

For C.I

FOR 1ST YEAR

I=( 4000×10×1)/100

= 400

AMOUNT= 4000+400 = 4400

FOR 2ND YEAR

I=(4400×10×1)/100 = 440

AMOUNT = 4400+440=4840

FOR 3RD YEAR(HALF YEAR)

I=(4840×10×1/2)/100 = 242

AMOUNT = 4840+242= 5082

C.I.= 5082-4000

= 1082

DIFFERENCE = 1082-1000

= 82

Answer 2

Answer:

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Step-by-step explanation:

principal = 4000

rate on interest = 10 % p. a

time = 2.5 year

first we calculate the amount for 2 year using the compound interest formula

A = p ( 1 + r/100 ) n

A = 4000 (1 + 10/100 ) 2

A = 4000 * (1.1) 2

A = 4840

we will calculate the interest on 4840 for 0.5 years @ 10%

interest = 4840 * 0.5 * 10 / 100

interest = 242

interest on first year = 400

interest on 2nd year = 440

interest on 4840 for the 0.5 more years rupees 242

total compound interest in

400 + 440 + 242 =

1082