Math, asked by VN1234, 4 months ago

The difference between simple and compound interest compounded annually on a certain sum of money for 2 years at 4% per annum is Rupee 1. Find the principal.

Answers

Answered by shrutisethi132
1

SI - CI = Rs. 1

P = Rs.?

n = 2 years

r = 4%

Difference between simple interest and compound interest for 2 years

 = p( { \frac{r}{100} )}^{2}

1000 = p \times  {( \frac{4}{100} })^{2}

p = rs.625000

Answered by Anonymous
5

\bf{  :  \implies SI - CI = Rs. 1} \\ \bf{  : \implies P = Rs.?} \\ \bf{ :  \implies n = 2 years} \\ \bf{ :  \implies r = 4 \%} \\ \bf{ :  \implies Difference  \: between  \: simple \:  interest \:  and}   \\ \bf{ \: compound \:  interest  \: for  \: 2 \:  years}

\bf{ :  \implies p =  (\frac{r}{100} )^{2}} \\\bf{ :  \implies 1000 = p \times (\frac{4}{100} )^{2}} \\ \bf{ :  \implies p = rs \: 625000}

 \large \sf \red{ \therefore the \: principal \: is \: 625000}

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