''the difference between simple and compound interest on a sum of money at 5 percent per annum is rupees 61 find the sum''
pls fast
Answers
Answered by
0
Answer:
Step-by-step explanation:
Answered by
1
The difference between simple interest and compound interest is Rs. 25 . So according to formula,Simple interest is
=>I=(P×R×T)/(100)=>I=(P×R×T)/(100)
=>P=(I×100)/(R×T)=>P=(I×100)/(R×T)
Compound interest formula
=> FV = P×(1+R/100})^THere FV = P + Total Interest=> I = P×(1×R/100)^T -P
So by equating condition mentioned in question where R=5% and T=2 years and difference is 25
=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×R×T)/100+25=P×(1+R/100)T−P
=>(P×5×2)/100+25=P×(1+5/100)2−P=>(P×5×2)/100+25=P×(1+5/100)2−P
=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=P∗(1.05)2−P
=>(10P+2500)/100=0.1025P=>(10P+2500)/100=0.1025P
=>(10P+2500)=10=>(10P+2500)=10.25P25P
=>0.25P=2500=>0.25P=2500
=>P=2500/0.25=>P=2500/0.25
=>10000=>10000
Hopes that answers your question.
Edit: made mistake in calculation when multiplying 0.1025 with 100, corrected
=>I=(P×R×T)/(100)=>I=(P×R×T)/(100)
=>P=(I×100)/(R×T)=>P=(I×100)/(R×T)
Compound interest formula
=> FV = P×(1+R/100})^THere FV = P + Total Interest=> I = P×(1×R/100)^T -P
So by equating condition mentioned in question where R=5% and T=2 years and difference is 25
=>(P×R×T)/100+25=P×(1+R/100)T−P=>(P×R×T)/100+25=P×(1+R/100)T−P
=>(P×5×2)/100+25=P×(1+5/100)2−P=>(P×5×2)/100+25=P×(1+5/100)2−P
=>(10P+2500)/100=P∗(1.05)2−P=>(10P+2500)/100=P∗(1.05)2−P
=>(10P+2500)/100=0.1025P=>(10P+2500)/100=0.1025P
=>(10P+2500)=10=>(10P+2500)=10.25P25P
=>0.25P=2500=>0.25P=2500
=>P=2500/0.25=>P=2500/0.25
=>10000=>10000
Hopes that answers your question.
Edit: made mistake in calculation when multiplying 0.1025 with 100, corrected
sourav171102:
pls mark brilliant
Similar questions