Math, asked by DHANANJAYNAIK1561, 1 year ago

The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 12% per annum is rs 72. what is the value of given sum (in rs)?

Answers

Answered by Anonymous
1
C.I for 2 years = P[(1 + r/100)]^2 - P
S.I for 2 years = PR*2/100

C.I - S.I = 72

72 = P[(1 + 12/100)^2] - P - P*12*2/100
72 = P[(112/100)^2] - P - P*24/100
72 = P[(28/25)^2] - P - 6*P/25
72= P{[784/625 - 1 - 6/25]}
72 = P[784-625-150/625]
72 = P[9/625]
P = 5000 Rs.
Similar questions