Math, asked by samiyafatimasami, 2 days ago

the difference between simple and compund interest on a sum put out for 5 years at 3% was 46.80. Find the sum
please explain step by step
(answer : 5200)​

Answers

Answered by tennetiraj86
42

Step-by-step explanation:

Given :-

The difference between simple and compund interest on a sum put out for 5 years at 3% was 46.80.

To find :-

Find the sum ?

Solution :-

Let the sum be Rs. X

Time (T) = 5 years

Rate of interest (R) = 3%

We know that

Simple Interest (S.I) = PTR/100

=> S.I = (X×5×3)/100

=> S.I = 15X/100

=> S.I = 3X/20

=> S.I = 0.15X

The Simple Interest for 5 years is

Rs.0.15X

We know that

Amount (A) = P[1+(R/100)]^n

=> A = X[1+(3/100)]⁵

=> A = X[(100+3)/100]⁵

=> A = X(103/100)⁵

We know that

Interest = Amount - Principle

=> Compound interest = X(103)/100)⁵-X

=> C.I = [(103)⁵X-(100)⁵X]/(100)⁵

=> C.I = (11592740743X-10000000000X)/(100)⁵

=> C.I = 1592740743X/(100)⁵

=> C.I = 1592740743X/10000000000

=> C.I = 0.1592740743X

=> C.I = 0.159X

(Correcting it upto three places )

The Compound Interest for 5 years is

Rs. 0.159X

Given that

The difference between simple and compund interest on a sum put out for 5 years at 3% was 46.80.

We have C.I = 0.159X and S.I = 0.15X

Difference = C.I - S.I

=> 0.159X - 0.15X = 46.80

=> 0.009X = 46.80

=> X = 46.80/0.009

=> X = (4680/100)/(9/1000)

=> X = (4680×1000)/(9×100)

=> X = 46800/9

=> X = 5200

Therefore, The sum = Rs. 5200

Answer:-

The required sum for the given problem is Rs. 5200

Used formulae:-

→ Simple Interest = PTR/100

→ Amount = P[1+(R/100)]^n

→ Amount = Principle + Interest

  • P = Principle
  • T = Time
  • R = Rate of interest
  • n = Number of times the interest is calculated compoundly.
Answered by Dalfon
261

Answer:

5200

Step-by-step explanation:

Given that the difference between simple and compund interest on a sum put out for 5 years at 3% was 46.80.

SI = (P × R × T)/100

Where R = 3%, T = 5 years and difference = Rs. 46.80

Let's say the principal is x.

SI = (x × 3 × 5)/100

SI = 15x/100

SI = 0.15x

CI = P(1 + R/100)^T - P

Substitute the values,

CI = x(1 + 3/100)⁵ - x

CI = x(103/100)⁵ - x

CI = x × 11592740743/10000000000 - x

CI = x × 0.159

CI = 0.159x

Now,

Difference = CI - SI

Substitute the values,

→ 46.80 = 0.159x - 0.15x

→ 46.80 = 0.009x

→ x = 46.80/0.009

→ x = 5200

Therefore, their sum is Rs 5200.

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