Math, asked by hemant337, 6 months ago

The difference between simple interest and compound interest on a certain principal for 2 years at 4% is Rs. 36. Find the principal.​

Answers

Answered by Anonymous
62

 \huge\boxed {\orange{\bigstar {\red{answer}}}}

We first find the simple interest and compound interest assuming the principal to be Rs. x. Then, find the difference between S.I. and C.I. Taking this difference for Rs. x we can find the principal.

let \: the \: prinecipal \: P = rs.x , \:  R = 4\% \: and \: N = 2yrs

simple \: interest

I =  \frac{P \times N \times R}{100}  =  \frac{x \times 2 \times 4}{100}  =  rs.\frac{8x}{100}

now \: compound \: interest \: is

A =  P(1 +  \frac{R}{100}   {)}^{n}  = n(1 +  \frac{4}{100}  {)}^{2}  = x(1.04 {)}^{2}  = (1.0816)x \: rs.

Hence  \: compound \:  interest = 1.0816x -  x = 0.0816x

Now, \: C.I.-S.I. = 0.0816x -  \frac{8x}{100}  =  \frac{8.16x - 8x}{100}  =  \frac{0.16x}{100}

The difference in CI and SI is Rs. 0.16 when the principal is Rs. x.

But the difference is Rs. 36 then the principal

is \: x =  \frac{100}{0.16}  \times 36 = 22,500.

thus \: the \: principal \: is

 \boxed{rs.22,500}

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