the difference between square of two number is 120. the square of smaller number is twice the greater number. find the numbers.
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Ok take one no as a and second as b
a^2 - b^2 = 120 st 1
(b^2 is smaller to a^2)
b^2 = 2a st 2
ok so continuing statement 1
-b^2 = 120 - a^22
b^2 = a^2 - 120
2a = a^2 -120(by statement 2)
2a - a^2 = -120
2a - a= -√120
a = -√120
thus b = 0 (substitute in st 1)
please mark as Brainliest
a^2 - b^2 = 120 st 1
(b^2 is smaller to a^2)
b^2 = 2a st 2
ok so continuing statement 1
-b^2 = 120 - a^22
b^2 = a^2 - 120
2a = a^2 -120(by statement 2)
2a - a^2 = -120
2a - a= -√120
a = -√120
thus b = 0 (substitute in st 1)
please mark as Brainliest
sweetgirlliya:
the 3rd line from last onwards are wrong
I couldn't get it what was wrong could you explain it?
2a - a2= - 120
then a2- 2a -120=0
then uh have 2 solve it
Yeah by factrizing its possible.
yah I was also answering this but because of factorisation I stopped answering it .
I checked like 4 times it dosent factorise so i guess this method would be right maybe
no but this method is not right ....
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