Question

The difference between the abscissa of (-4,7) and ((1,-5) is​

Answer 1

GIVEN :-

• Two points (-4,7) and (1,-5)

TO FIND :-

• The distance between them.

SOLUTION :-

As we know, that the distance formula is given by,

✭ Distance between them,

➟ D = √{ (x2 - x1)² + (y2 - y1)²}

• x2 = 1
• x1 = -4
• y2 = -5
• y1 = 7

➟ D = √[ {1 - (-4)}² + { -5 - 7}² ]

➟ D = √{ (1 + 4)² + (-12)² }

➟ D = √{ (5)² + 144 }

➟ D = √(25 + 144)

➟ D = √169

➟ D = 13

Hence trains between the points (-4,7) and (1,-5) is 13 units.

Answer 2

${\huge {\tt {\underline {\underline{solution}}}}}$

$\tt{As \: we \: know, \: that \: the \: distance \: } \\ \tt{formula \: is \: given \: by,}$

$\tt{d = \sqrt{(x2 - x1)^{2} } } + \sqrt{ (y2 - y1) ^{2} }$

$\tt{x2 = 1}$

$\tt{x1 = - 4}$

$\tt{y2 = - 5}$

$\tt{y1 = 7}$

$\tt \: d = { \sqrt{1 - ( - 4) ^{2} }} + (- 5 - 7 )^{2}$

$\tt{d = \sqrt{(1 + 4) ^{2} } } + ( - 12) ^{2}$

$\tt{d = \sqrt{ {(5)}^{2} + 144 } }$

$\tt{d = \sqrt{169}}$

$\tt{d = 13}$