The difference between the ages of 2 cousins is 10 years. 15 years ago, the elder one was twice as old as the younger one. Find their present ages.
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The difference between the ages of two cousins is 10 years. 15 years ago, if the elder one was twice as old as the younger one, find their present ages. Solution. 10 + �� − 15 = 2(�� − 15) → �� = 25 → �� = 35 Answer.
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Let Present age of younger cousin = x
Then age of older cousin ll be = x + 10
15 years ago:
Age of younger cousin = x-15
Age of older cousin = x+10-15 = x-5
According to question,
=> x-5 = 2(x-15)
=> x -5 = 2x -30
=> 2x-x = -5+30
=> x = 25
So age of younger cousin = 25 years
Age of older cousin = 25+10 = 35 years
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