Question

The difference between the ages of a father and his son is 24 yeras currently five years ago the sons was one third of his fathers age find the age of each.

Answer 1

i am denoting father as F , son as S
F-S = 24 --------- (1) equation
5 years ago
Father's age =(F-5)
Son's age = (S-5)
1/3 × (F-5) = (S-5)
F-5 = 3S - 15------- equation (2)
now from equation (1) F=24+S
put this value in equation (2)
24+S -5 = 3S-15
2S = 34 or S = 17
put value of S in equation (1)
F= 24+S = 24+17 = 41
Father's age = 41
son's age = 17

Answer 2

Step-by-step explanation:

Adding 8 to 7 results in a sum of digits of 6, and so on down to adding 8 to 1 which gives 9.

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Number Repeating Cycle of Sum of Digits of Multiples

10 {1,2,3,4,5,6,7,8,9}

11 {2,4,6,8,1,3,5,7,9}

12 {3,6,9,3,6,9,3,6,9}

13 {4,8,3,7,2,6,1,5,9}