Question

The difference between the ages of two brothers is 12 years if 10 years ago the elder one was twice as old as

Answer 1

age of elder one = x

age of younger one  = y

x - y = 12

x = 12 + y

10years ago

younger one = y - 10

elder one = x - 10 or 2(y - 10)

12 + y  - 10 = 2y - 20

y = 22

x = 22 + 12 = 34

age of elder one = 34

age of younger one = 22