Question

the difference between the ages of two cousins in 10 years . 15 year ago , if the elder one is twice as old as the younger one find their present age​

Answer 1

Answer:

younger one - 25

elder one - 35

Step-by-step explanation:

let the age of younger one be x

and the elder one be x+10

15 years ago

age of younger one = x-15

age of elder one = x+10-15 = x-5

given, 15 years ago elder one was twice as old as the younger one

Now, forming equation

2(x-15) = x-5

2x-30 = x-5

2x-x = -5+30

x = 25

Hence,age of younger one = x = 25

age of elder one = x+10 = 25+10 = 35

Answer 2

Answer:

let the age of first cousin be x

therefore the age of second cousin =10 + x

the age of first cousin before 15 years = x -15

and the age of second cousin equal to x + 10 - 15

ATP,

(x+10)-15= 2(×-15)

=>×+10-5=2×-30

=>-×= -35-10

=>-×=-45

=>×=45

therefore the age of first cousin equal to 45