Question

The difference between the ages of two cousins is 10 years ago,if the elder one was twice as old as the yonger one,find their present ages​

Answer 1

Answer:

Step-by-step explanation:

Let the age of smaller brother be x

Then,

The age of the elder brother is 2x

Then,

2x-x=10

x=10

Thus,

The age of smaller brother is x=10,

The age of elder brother is 2x=20.

Answer 2

Answer:

x = 20 and y = 10

Step-by-step explanation:

let elder be x and younger be y.

x - y = 10 -(i)

x= y

x = 2y

x - 2y = 0 -(ii)

we do elimination method in eqn i and ii

x - y = 10

x - 2y = 0

-  +        -

0 +y = 10

y = 10

from eqn (i)

x - y = 10

x - 10 = 10

x = 10 + 10

x = 20