Question

The difference between the ages of two cousins is 10 years.15 years ago,if elder one was twice as old as younger one,Find their present ages​

Answer 1

Answer:

15 and 25 years old

Step-by-step explanation:

Define their age in term of x:

Let one of them be x.

The other is x + 10.

Define their age 15 years ago:

one of them = x - 15

The other = (x + 10) - 15 = x - 5

The elder was twice as old as the younger one:

x - 5 = 2(x - 15)

Solve x:

x - 5 = 2(x - 15)

x - 5 = 2x - 20

x = 15

Find their present age:

one of them = x = 15 years old

the other = x + 10 = 15 + 10 = 25 years old

Answer: They are 15 and 25 years old.