Math, asked by wwwshubhamsingh637, 7 months ago

the difference between the ages of two cousins is 10 years. 15 years ago if the elder one was twice as old as the younger one find their present age?​

Answers

Answered by asahilthakur
5

Answer:

Let the present age of the younger cousin be x.

Present age of elder cousin = x + 10

Age of younger cousin 15 years ago = x - 15

Age of elder cousin 15 years ago = x + 10 - 15 = x - 5

According to Question,

2 (x - 15) = x - 5

=> 2x - 30 = x - 5

=> 2x - x = 30 - 5

=> x = 25

Hence, present age of younger cousin = 25 years

Present age of elder cousin = 25 + 10 = 35 years

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