the difference between the ages of two cousins is 10 years. 15 years ago if the elder one was twice as old as the younger one find their present age?
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Answer:
Let the present age of the younger cousin be x.
Present age of elder cousin = x + 10
Age of younger cousin 15 years ago = x - 15
Age of elder cousin 15 years ago = x + 10 - 15 = x - 5
According to Question,
2 (x - 15) = x - 5
=> 2x - 30 = x - 5
=> 2x - x = 30 - 5
=> x = 25
Hence, present age of younger cousin = 25 years
Present age of elder cousin = 25 + 10 = 35 years
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